Java中根据Json对象拿到对应的Key和Value值

例如：如下Json

{
    "touSer":"123456789",
    "templateld":"cuUWTKzm1AaKqfmb5MIbSqxvvGc28DgpcllPyPcnoZE",
    "data":[
        {
            "value":"你好！！！",
            "color":"#fa3534"
        },
        {
            "value":"您好！！！",
            "color":"#fa3534"
        },
        {
            "value":"她好！！！",
            "color":"#fa3534"
        },
        {
            "value":"我好！！！",
            "color":"#fa3534"
        },
        {
            "value":"大家好！！！",
            "color":"#fa3534"
        }
    ]
}

方法一：

    public void postTest(@RequestBody String res) {
        JSONObject object=JSONObject.parseObject(res); // 把字符串转换为Json对象
        String template_id=object.getString("templateld");
        JSONArray data=object.getJSONArray("data");
        System.out.println(template_id);
        System.out.println(data.get(0));
    }

getString方法：拿到字符串类型key
getJSONArray方法：拿到数组类型key，然后可以get(i)取出你需要的值

方法二：

    public class User {
        private String touSer;
        private String templateld;
        private JSONArray data;
    }

    public void postTest(@RequestBody User user) {
        System.out.println(user.getTemplateld());
        JSONArray data = user.getData();
        System.out.println(data.get(0));
    }

定义一个实体类然后直接点就行了，实体对象类型对应json类型

扩展

分解data数组

        JSONArray data = user.getData(); // 拿到Data数组
        JSONObject object = data.getJSONObject(0);  //数组转化成JSON对象
        System.out.println(object.getString("value"));  //输出对象
        System.out.println(object.getString("color"));  //输出对象